Friday, 5 February 2016

CLASS XI MODEL QUESTION PAPER IN CHEMISTRY

KENDRIYA VIDYALAYA AFS AVADI CHENNAI- 600055
MODEL QUESTION PAPER –  2016
CHEMISTRY
Time : 3 Hrs.                                                                                        Max.Mark: 70
Class:XI
Instructions:
·         Answer all the questions.
·         Questions 1 to 5 are very short answer type and carry one mark each. Answer them in one word or in one sentence.
·         Questions 6 to 10 are short answer type and carry 2 marks each. Answer them in 20 words.
·         Questions 11 to 22 are short answer type and carry 3 marks each. Answer them in 30 words.
·         Question 23 is value based question and carry 4 marks. 
·         Questions 24 to 26 are long answer type and carry 5 marks each. Answer them in 50 to 60 words.
·         All 5 mark questions, one 3 mark question and one 2 mark question have internal choice. There is no overall choice.
·         Use log book wherever needed. Use of calculator or any other electronic item is strictly prohibited.

1
Express the following in the scientific notation:  i)  0.0048  ii)  8008 

1
2
What do you understand by the term auto protolysis of water?      
1
3
What is the basic principle of Hydrogen economy?
1
4
Calculate the number of atoms in   13 moles of He.                
1
5
Predict the formulae of the stable binary compounds that would be formed by the combination of the following pairs of elements i) Lithium and oxygen   ii)  magnesium and nitrogen  
1
6
Distinguish between a sigma and a pi bond.
                         OR
  Although both CO₂  and H₂O are triatomic molecules the shape of H₂O molecule is bent while that of CO₂ is linear. Explain this on the basis of dipole moment?
1+1
7
a.What is photochemical smog?
b.What is BOD?

8
a)Alkali metals are good reducing agents.Why?

b)Why are Potassium and Cesium, rather than Lithium used in photoelectric cells?           
2
9
 Using s, p, d, f notations, describe the orbital with the following quantum numbers
      (a) n = 2, l = 1, (b) n = 4, l = 0,

2
10
a) CH₃ - CH₂ – CH – CH = CH - CH₂ - CHO
                             |
                           CH3

(b) CH₃ - CH₂ - CH - CH₂ - CH - CH₃
               |                   |
              CH₂OH       CH₂-CH₃  
2
11
a)State Hess’s law of constant heat summation.
b)         In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system.  What is the change in internal energy for the process?
c)         For the reaction, 2Cl (g) à  Cl2 (g), what are the signs of ∆H and ∆S?
3
12
a)What is an electrophile?  Give example.
b)         Why is it necessary to use acetic acid and not sulphuric acid for acidification of sodium extract for testing sulphur by lead acetate test? 
3
13
What happens when
a)      Borax is heated strongly
b)      Boric acid is added to water
c)Aluminium is treated with dilute NaOH.                
3
14
. Predict in which of the following, entropy increases/decreases:(i) A liquid crystallizes into a
solid.(ii) Temperature of a crystalline solid is raised from 0 K to 115 K.(iii) H2(g)   à 2H(g)
                                                 OR
(a) Write the conditions in terms of ∆H and ∆S when a reaction would always spontaneous.
(b)  For the reaction at 298 K
            2A +B ® C
            ∆H = 400 KJ mol-1 8∆S = 0.2KJmol-1 k-1 At what temperature will the reaction become spontaneous?


3
15
Given the standard electrode potentials,K+/K = –2.93V, Ag+/Ag = 0.80V,Hg2+/Hg = 0.79V
Mg2+/Mg = –2.37V. Cr3+/Cr = –0.74V, Cu2+/Cu = 0.34V. Arrange these metals in their   
       increasing order of reducing power.

3
16
a)      Classify the following species into lewis acids and bases
OH-,     BF3,       H+,      F-
b)      Calculate the PH of 0.02M KOH
c)      H2O can base, write its corresponding conjugate base and conjugate Acid

3
17
           
a)Draw cis and trans isomers of the following compounds and also write their IUPAC names.
i)                    CHCl=CHCl   ii)  CH3CH=CHCH3
b)         What is metamerism?  Give example.
           
                                               
3
18
1.      Give reasons for the following:
            (i) Cations are smaller than neutral atoms.
            (ii) Fluorine has lower electron-gain enthalpy than chlorine.
            (iii) Sulphur has lower ionization enthalpy than phosphorus.

3
19
a)         In the estimation of sulphur by carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate.  Find the percentage of sulphur in the given compound.             


20
a)         State Markovnikov’s rule.
b)How will you convert benzene into acetophenone
3
21
.
(a)   n- pentane has high b.p than neo-pentane why ?
(b)   Write the structure of 3,4 di-methy hept-3-ene
(c)    Give an example for pyrolysis

3
22
Complete the following chemical reactions.                                                            
i)                    PbS (s)   +   H2O2 (aq)  à
ii)                  MnO4-  (aq) + H2O2 (aq)  à
iii)                Fe3+ + H2O 2 (l)+OH_  à 

3
23
Scientists have harnessed the principles of photosynthesis to develop a new way of production of Hydrogen in a breakthrough that offers a possible solution to global energy problems. The researchers claim the development could help unlock the potential of Hydrogen as a clean, cheap and reliable power source. Hydrogen can be burned to produce energy without producing emissions like those produced by burning of fossil fuels. Hydrogen is produced by electrolysis of water. Scientists have separated water into Hydrogen and Oxygen in a way similar to plants’ usage of Sun’s energy to split H2O molecules into H2 and O2. This research offers a promise in making storage of green energy cheaper. Based on this information, answer the following questions:
            (i) Name the most abundant element in the universe.
            (ii) What are the values exhibited by these scientists?
            (iii) Why is H2 an ideal fuel?
            (iv) What are the disadvantages of using H2 as a fuel?
.

3
24
a)Alkane ‘A’ contains three C-C, eight C-H ϭ bonds and one C-C π bond.  ‘A’ on ozonolysis gives two moles of an aldehyde of molar mass 44 amu.  Write IUPAC name of ‘A’.
b)Write the reaction between (a) hex-1-ene and HBr (i) as per Markownikoff’s rule (ii) as per peroxide effect




25
a) Boron is unable to form BF6, why?
b) Suggest a reason as to why CO is poisonous.
c) Conc.HNO3 can be transported in aluminium container. Why?
d) What happens when boric acid is heated strongly?
e) What happens when CO is heated with ZnO?
          
                              OR

a) Boric acid is considered as weak acid. Give reason.
b) Select the members of the group 14 that (i) form the most acidic oxide
     ii) is commonly found in +2 oxidation state.
c) Diamond is covalent, yet it has high melting point. Why?
d) White fumes appear around the bottle of anhydrous aluminium chloride. Give reason
e) How is synthetic gas produced commercially?
5






26
How would you explain
            (i) why is sodium less reactive than potassium?                               


            (ii) Why is Li2CO3 decomposed at a lower temperature whereas Sodium carbonate at higher temperature
            (iii)LiI is more soluble than KI in enthanol.
iv).Lithium on being heated in air mainly forms the monoxide not peroxide.
v).BeCO₃ is less stable than  MgCO₃.

2.Alkali metals are used in photoelectric cells.
3.LiCl is predominantly covalent while NaCl is ionic .




SCORING KEY
1
i)     4.8x10-3  ii)   8.008x103                                   
½ + ½
2
.  Autoprotolysis refers to self ionisation of water
               H2O(l)  +  H2O(l)   ↔  H3O+ (aq) +  OH- (aq)                                                                                                                                                                     
                Acid1          Base2             Acid2             Base1

1
3
Transportation and storage of energy in the form of liquid or gaseous Dihydrogen
1
4
1 mole of He has 6.022x1023atoms, so 13 moles of He has
            13x6.022x1023 = 7.83x1024 atoms.     
1
5
i)  Li2O   ii)   Mg3N2 
½ + ½
6

Sigma (ϭ) bond                                                Pi (π) bond
It is formed due to axial                               This bond is formed by the                                              
 overlap of the two orbitals                        lateral overlap of two p-
 The bonding is relatively strong.               Orbitals
                                                                   The bonding is weak
                                              OR
The Dipole moment  is zero in CO2  and
 the resultant Dipole moment    for H2O is ≠ 0 this indicates bent structure for H2O molecules because bond moment of two O-H bonds do not cancel out.                                                                                                                        
                                                                                                 O
O         C          O                                                           H                        H              1
Resultant µ = 0                                                          Resultant µH=1.84D

1+1
7
a.Active  oxygen atoms react with traces of hydrocarbons present in the  atmosphere and produce  health hazardous materials called photochemical smog.
B.Bio oxygen demand is a measure of the oxygen utilized by microorganisms during oxidation of organic materials

7
molarity = 3M
Mass of NaCl in 1 litre solution = =3x58.5 = =175.5g                                                            Mass of 1L solution = 1000xdensity
                                 =1000x1.25 = 1250g                                                                              
Mass of water in solution = 1250 – 175.5 = 1074.5g                                                       
Hence. Molality(m) = moles of solution / mass of solvent in kg
= 3/1.0745 = 2.79m


1/2

1/2

1/2
1/2



8

(a)alkali metals have very low ionisation enthalpy. Hence they can lose their valence electron  readily and can bring about reduction                                                                                        
b.The ionization energies of Potassium and Cesium are much lower than that of Lithium.
1+1
9
a) 2p  (b) 4s 
1+1
10
(a)   5-methylhept-3-en-1-ol.
(b)2-ethyl-4-methylhexan-1-ol.
1+1
11
a)Hess’s law of constant heat summation states that “The enthalpy change during a chemical reaction is independent of the manner in which the change is brought about”
b)         Heat absorbed by the system, q = + 701 J
Work done by the system    w = -394 J
Change in the internal energy, ∆U = +701 – 394 = + 307 J.
c)         For the given reaction, ∆H is negative and ∆S is negative.
1


1



1
12
a)A reagent that takes away an electron pair is called an electrophile (E+) i.e., electron seeking and the reaction is called electrophilic. 
Example:  carbocations and neutral molecules having functional groups like carbonyl group or alkyl halides.
b)         This is because if sulphuric acid is used, it will decompose sodium sulphide (Na2S) formed during fusion.  As a result, the solution will give a negative test for the presence of sulphur in the sample.                                                




      1½

     1½
13
a)         When Borax is heated strongly, it loses water of crystallization and forms colourless, transparent glass-like bead which is made up of sodium metaborate and boric anhydride.                         ∆                   ∆
Na2B4O7.10H2O    àNa2B4O7à  2NaBO2 + B2O3
b)         When Boric acid is added to water, it accepts a hydroxyl ion and behaves as a Lewis acid.
            B(OH)3  +  H2O    à  [B(OH)4]-   +  H+
c)         When aluminium is treated with NaOH, it forms aluminates and hydrogen gas is liberated.
            2Al  +  2NaOH  + 2H2à   2NaAlO2  + 3H2 (g)                               
1




1



1
14
(a)   decreases  (b) increases  (c) increases


a)∆G =  ∆H - T∆S
            High T,  Low ∆S and High ∆H
            (b) ∆G = ∆H- T∆S                                            
            Let ∆G =0
            0= 400 –T (0.2)
            200
= T
            0.1
            T= 2000 K
Above 2000k
       
                                                             

1+1+1


1






1





1
15
The lower the electrode potential, the stronger is the reducing agent. Therefore, the increasing order of the reducing power of the given metals is Ag < Hg < Cu < Cr < Mg < K.
3
16
a) Lewis Acids :           BF3, H+                                                                 Lewis bases   :           OH-, F-
            (b)        PH= 14 – POH
                        PoH= log ( 2x10-2)
                        POH= log 2+2
                        PH= 14+log2-2
                            =12+0.3010
                           =12.3010      
C)H2O accepts as well as donete H+ hence it acts on both acid & base
H3O+ ¬ H2O®OH-    
1

1






1
17
 
b)It arises due to different alkyl chains on either side of the functional group in the molecule. 
Example:  C4H10O represents methoxypropane (CH3OC3H7) and ethoxyethane (C2H5OC2H5).

1

1

1
18
. (i) Cations are formed by loss of electrons, keeping protons the same. So, effective nuclear charge increases and size decreases.
(ii) It is due to more inter-electronic repulsions in F than in Cl.
(iii) It is due to stability of half-filled p-orbitals in P and not in S.

1

1
1
19
Percentage of sulphur in the compound   =  mass of BaSO4x32x100/233xmass of the compound.
            =  0.668x32x100/233x0.468 = 19.6%
Percentage of sulphur in the compound  =  19.6%   


20
Markovnikov’s rule states that the negative part of the addendum gets attached to that carbon atom which possesses lesser number of hydrogen atoms

Benzene can be converted into acetophenone by the reaction of benzene with acetyl chloride.


21
a) Due to strong Vander waals forces.
   +   +  +

           
           

                  6           5        4     3    2     1
            (b) H3 C- H2C-C= C-CH-2 CH3
          I     I
         CH3CH3                    
           

            (c) C2 H6® CH2= CH2 + H2
           


22
i)PbS (s)  + 4H2O2 (aq)  à4 H2O + PbSO4
             6H+
ii)       2MnO4-  (aq) + 5H2O2 (aq) à2Mn2+ (aq) + 8H2O + 5O2 (g)
iii)2Fe3+ + H2O 2 (l)+2OH_  à 2Fe2+ +  2H2 O   + O2

23
i ) Hydrogen.
(ii) They show care for the environment and concern for global problems.
(iii) It has highest calorific value and produces H2O as the only by-product, which harmless.
(iv) It is highly inflammable and its storage needs extra care.

1
1
1

1
24
a)But-2-ene
b)CH3CH2CH2CH2CH=CH2 + HBr  à
CH3CH2CH2CH2CH(Br)CH3
 CH3CH2CH2CH2CH=CH2 + HBr  (in the presence of peroxide)à
CH3CH2CH2CH2CH2CH2Br

2
1


1
25
a) Due to non-availability of vacant d orbital
b) Competes with O2 for hemoglobin and is bonded to hemoglobin
     so that O2 is not carried to cells
c) Passive layer of Al2O3 acts as a protective layer
d) Forms HBO2 and then B2O3
e) Co2 + Zn is formed

                                                  OR

a) Not able to release H+ ions  on its own
b) i) C    ii)  Pb
c) 3 dimensional network involves strong C-C bonds, difficult to
    break
d) Anhydrous AlCl3 hydrolyses partially with atmospheric moisture
     to liberate HCl gas and moist HCl appear white
e) Passing steam over red hot coke  with equation


1
1

1
1
1
26
i)Sodium and potassium both are electropositive elements.  The ionization enthalpy of potassium is lesser than that of sodium.  That is why potassium is more reactive than sodium.  So, sodium is less reactive than potassium
ii)Lithium ion is small in size, whereas carbonate ion is a large anion.  A substance containing a small cation and large anion are less stable.
iii)lithium ion, due to it smaller size, has greater polarising power hence covalent so soluble
iv) Li+ ions is smaller in size it is stabilized more by smaller anion oxide ion(O2-) as compare to larger anion peroxide (022-)                                                                                                   
v) Be2+ ion is smaller in size than Mg2+ ion.
Be2+ion does not form stable lattice with carbonate ion which is quite larger in size. Mg2+ ion being larger forms relatively stable lattice with cabonate ion.                                               


 (b)alkali metals because of their low ionisation enthalpy can lose electron easily on irradiation , hence they are used in photoelectric cells                                                                             1
(c) than sodium ion, hence LiCl predominatingly is covalent while NaCl is ionic.                                                                        1
(d a.Lithium ion is small in size, whereas carbonate ion is a large anion.  A substance containing a small cation and large anion are less stable












No comments:

Post a Comment